Preventive Maintenance Stevenson ( two hundred9) includes problem 15S-3 to determine the optimal preventive sustenance frequency for each of the pieces of equipment if breakdown is ordinarily distributed (p.732) The table at a lower place provides the following given(p) information: EquipmentAverage time amidst breakdowns (Days)Standard DeviationPreventive Maintenance Cost crack Cost A201202$300 $2,300 B400303$200 $3,500 C850404$530 $4,800 According to Stevenson (2009), an optimal fear time interval for equipment, given the modal(a) time between breakdowns and model deviation, provides trading opeproportionns managers a decision-making tool for preventive maintenance with the interminable practical use of facilities or equipment without a breakdown (p. 730). Stevenson (2009) suggests first, victimisation the ratio Preventive Cost/Breakdown Cost = luck to preserve the cost of preventive maintenance to the cost of a breakdown repair, then determining z, i.e., the number of standard deviations from the misbegot and adding the average time between breakdowns, optimal maintenance intervals for each pillowcase of equipment would be: EquipmentProbabilityZMean + Z = optimum Maintenance legal separation A201$300/$2,300 = .1301.1220 1.12(2) = 17.76 days B400$200/$3,500 = .0571.5830 1.58(3) = 25.26 days C850$530/$4,800 = .1101.2240 1.22(4) = 35.12 days sort of of reading the z table values from the text, an online z-score calculator fundament be used to find the number of standard deviations from the mean, given a probability ( ordinance Lab, n.d.). References verbal expression Lab. (n.d.). Z-score calculator [online application]. Retrieved from Formula Lab website http://www.fourmilab.ch/rpkp/experiments/analysis/zCalc.html Stevenson, W. (2009). Operations Management (10th ed.). newly York, NY: McGraw-Hill.If you urgency to get a full essay, order it on our website: OrderCus tomPaper.com
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