Task 5 PROBABILITY, STATISTICS, & QUANTITATIVE PROBLEM Essay

Task 5 PROBABILITY, STATISTICS, & QUANTITATIVE PROBLEM - Essay Example Therefore cost subsequent to discount is x-0.1x=0.9x. Hence the cost before and after tax is X=0.9x. Company B; let the cost prior to discount be represented by y. Company B wont award discount if y≠¤20. Hence cost subsequent to discount is y. We end up with the equation y= given y≠¤20. Incase y exceeds 20, company B will award 20% discount for any amount more than 20 dollars. The amount more than 20 dollars is y-20.discount is 20/100 of (y-20) =0.2x-4. The cost y subsequent to discount is given by 0.8x+4. Hence the cost before and after tax is connected by y=x given x≠¤20, y=0.8x+4 given y>20 Company A: The cost prior to discount is not more than 20 dollars. Systems of equations to be solved are x=0.9x, y=x and y=y .it implies that x=y=y. therefore x=0.9x hence dividing both sides by x we get 0.hence solution to the systems is x=o, y=0 and z=0. It implies that incase purchases are more than 20dollars, the two companies’ offers are equal if they do not purchase at all. Incase x inclines from 0 to 20 company’s A offer is better as they give10% discount and no discount is given by company B. Company B: The cost prior to discount is more than 20 dollars. Systems of equations to be solved are y=0.9x, y=0.8x+4 and y=y meaning 0.9x=0.8x+4 which gives us 0.1x=4 hence x=40. Y=0.9Ãâ€"40=36 and y=y=36. The solutions to this system is therefore x=40, y=36 and y=36. It implies that incase purchases are more than 20dollars, the two companies’ offers are equal if the amount prior to discount is 40dollars.if 20